subtract and give the difference in number of months. Function to count workdays. 3. 25)) AS `numberofemployees`. WHERE -- >= 2016-02-01 00:00:00. The numbers to the left of the decimal point are the days, the numbers to the right is the decimal fraction. First you get the number of years from the birth date up to now. 9. So subtracting a TIMESTAMP WITH TIME ZONE that is 5 am Eastern from a TIMESTAMP WITH TIME ZONE that is 2 am Pacific will result in an interval of 0. For formatting functions, refer to Section 9. mm') 16. Converts one date format to a new format and returns the result. You should consider how many. There are many tricks to generate rows in Oracle Database. Sorted by: 193. FROM HR. There are similar questions on the site; however as I could see, none of them asks for an output as. DATEDIFF (MONTH, DATEADD (DAY,-DAY (startDate)+1,startDate),DATEADD (DAY,-DAY (startDate)+1,endDate)) Share. We’re calculating months of service in this example. CancelDate IS NOT NULL THEN (CONVERT(NVARCHAR(MAX), DATEDIFF(day, Trips. I have a creation date column in the table. Multiply the result of step 1 by 12 to transform it to months 3. Currently I am only returning 1. expression2: This is a datetime expression you’ll substract from expression1. DATEDIFF (datepart, startdate, enddate) which can return the difference in years, months, days etc. You will see column tools as one of the tabs. 1. For example: print &order_date () edit 'Month dd, YYYY'. Value, Fields!endDate. Then you use the TO_DATE () function to. I want to calculate the difference between two dates in OBIEE10g in Year/Months/Days format similar to the output of below SQL. A note on Databricks: Databricks additionally supports a separate DATEDIFF function that takes only two arguments: a start date and an end date. . The MONTHS_BETWEEN function returns an estimate of the number of months between two arguments. To answer your question to find all records that occurred last month. It returns a whole month (no fraction) if both dates have the same day-of-month or. The expression is given to calculate the month’s difference between two dates, use the date diff expression as shown below. however using the below sql statement im getting. Multiply by 24 -- hours, multiply by 60 minutes, multiply by 60 -- seconds. SELECT * FROM TABLE_NAME WHERE DATEADD (DAY, -90, GETDATE ()) between txtFromDate and txtToDate. 5 days to a given date. . current_time() returns the date and time on the database client side. 一重引用符で囲んだ'YYYY-MM-DD[*HH:MI[:SS]]'形式の文字列(*はコロン(:)または空白でも可)、または現在の日付を返す引用符なしの@DATENOW. Expressions that return a value of any of the following built-in data types: a date, a timestamp, a character string, or a graphic string. 1. NEW_TIME (date, timezone1, timezone2) Timestamp. Here, since you need to subtract one day, you use current_date – 1 . Extract a value of a date time field e. NEXT_QUARTERDatediff between dates, but exclude extra leap year day Forum – Learn more on SQLServerCentral. Exhibit A: John Doe has served since Feb 10, 2016. oracle; datediff; or ask your own question. The next example will show the differences between two dates for each specific datapart and abbreviation. ----- we travel not to escape life but for life not to escape us. Get the number of months between two dates. Example. trunc ( months_between ( end_date, start_date ) /12 ) Years, mod ( trunc ( months_between ( end_date, start_date ) ), 12 ) months, end_date - add_months (start_date,trunc ( months_between (end_date,start_date) )) days. For example when I place 01/01/04 as the. Functions. 242199 assumes that you want the number of solar years between 00:00 on the first date and 00:00 on the second date, to 9 significant figures. We will be using the same employees table in order to demonstrate the intricacies of calculating the difference between two dates in terms of weeks, months, or years using MySQL’s DATEDIFF() function. Teams. I had a problem with a date query using the operator 'between'. 32 illustrates the behaviors of the basic arithmetic operators ( +, *, etc. This function adds a number (a signed integer) to a datepart of an input date, and returns a modified date/time value. , year, quarter, month, day, hour, minute, second), startdate is the starting date or time, and enddate is the ending date or time. AT TIME ZONE. 25 = 0. 2425. SELECT DATEDIFF(day,'2008-06-05','2008-08-05') AS DiffDate from dual is not working in SQL ERROR : ORA-00904: "DATEDIFF": invalid identifier 00904. ) and the. 2425): datediff (day, {start-date}, {end-date},) / 365. You can even find the number of hours, minutes, seconds, and so on in terms of details in. The date functions are summarized in the table below. February 28 and March 28) and when the days of the month are the last day of the month (e. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. EXTRACT the number of years from the interval. UPDATE Yes, he will get a 1 month difference even if it is only 1 day difference, but OP. Improve this question. Viewed 2k times. Oracle offers its own solution, although does not have the DATEDIFF function. And determining if the date falls on a holiday (by querying against your holiday table) should be trivial. )? SELECT (TRUNC (SYSDATE+1) – SYSDATE) *24 *60 *60 AS NOS_OF_SECS_LEFT FROM DUAL; These are some most important SQL Date Functions Examples. e. My Oracle Support provides customers with access to over a million knowledge articles and a vibrant support community of peers and Oracle experts. 33 shows the available functions for date/time value processing, with details appearing in the following subsections. This question was incorrectly asked. Sep 16, 2015 at 5:55. Oracle equivalent to SQL Server/Sybase DateDiff. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input. Oracle datediff function. So, the difference between Jan 1 20015 and Dec 31 2016 is 1 year. It returns a whole month (no fraction) if both dates have the same day-of-month or both are the last day of the month. You want to pass TIMESTAMP arguments to the function and when you add years you also need to ensure that you propagate the fractional component of the timestamp (since ADD_MONTHS returns a DATE data-type without fractional seconds):Unfortunately, Oracle SQL doesn't allow the DATEDIFF function. Here is my trigger: SET NEW. Feb-N to Mar-N is commonly accepted as a "month". This is from my own library, will return the difference of months between two dates. 0. ToDate)); My SQL to LINQ Recipe might help you with some translation issues in the future. The math is 100% accurate for dates within a couple of hundred years or so. (You can also subtract fractions of days, but that might be outside the scope of this answer. SELECT EOMONTH ('02/04/2016') Returns 02/29/2016. Oracle Help Center - MONTHS_BETWEENyou ca also use LAG analytical function to get the desired results as : Suppose below is your input table: id account_number account_date 1 1001 9/10/2011 2 2001 9/1/2011 3 2001 9/3/2011 4 1001 9/12/2011 5 3001 9/18/2011 6 1001 9/20/2011 select id,account_number,account_date, datediff(day,lag(account_date,1) over (partition by. date]-90) - my comparison subtracts 90 days from the max date Yes, I know,. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. The following illustrates the syntax of the DATEPART. , a year, a quarter, a month, a week that you want to compare between the start_date and end_date. If date1 is earlier than date2, then the result is negative. @Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. The following example illustrates how to use the. SELECT * FROM EmployeeAttendance WHERE DateJoined BETWEEN '2021-01-01' AND '2022-12-31'; This query will return all employees who joined between January 1, 2021, and December 31, 2022. The difference between two dates (in oracle's usual database product) is in days (which can have fractional parts). And what date you want to get for example difference between dates 456 days it's mean: 1 year 3 month and several days. We will use the below date for the examples. - Find the “date_diff” in hours and multiply it by “60”. Add six months to a start date. 25) This seems to be another common approach - and was also given in a comment on my question. In case the full DDL for the database is requested, I can provide it (although it will probably exceed the character limit of Stackexchange). Then it would also be helpful to be able to remove holidays from this. Syntax @DATEDIFF (' difference ', ' date ', ' date ') difference. "Order Date") Description: Adds a specified number of intervals to a timestamp, and returns a single. Q&A for work. If you need to calculate minutes or seconds, you simply multiply the result by a constant: (date2 - date1)*1440 -- number of minutes (date2 - date1)*86400 -- number of seconds. DATEDIFF is a common function in the SQL Server to find the number of days between two dates. 0208 days. Oracle Oracle Database Release 19 SQL Language Reference MONTHS_BETWEEN Syntax Description of the illustration months_between. 9. for example Feb-15th to Mar-15th is a month. For example: Todays date: Jun 13, 2017. So, Feb-28 to Mar-28 is a month. Modified 5 years, 9 months ago. The Days, Months, and Years parameters can be negative or positive. Asked 5 years, 9 months ago. months_between/120 = decades_between. 4 Answers. I m used to sql server. Please note that with dates it is usually best to compare it this way: X >= lower bound AND X < upper bound. A string within single quote marks, in the format of 'YYYY-MM-DD[*HH:MI[:SS]]', where * can be a colon (:) or a blank space, or the. Taking example 1, Oracle is telling me that 3rd Feb was a longer time ago than Informatica is telling me it is. If this query is executed between December 26 and December 31, you'll still. メンバーの日. Therefore, if you’re looking for. BaseDate. Sample table: ProductID Date P101 31-DEC-2012 P102 29-DEC-2011 You get the difference in days. Access Function: DateDiff ("m",PAID_DATE,STATIC_DATE) AS Months_Between. It works if my beginning date is the first of january and the end date the 31st of December, but does not if it stars somewhere else during the year. Share. Thank you. For example the difference between 1st March 2011 and 3rd March 2012 is 1. SELECT DISTINCT Test, FIRST_VALUE (CONVERT(DATE, datetime)) OVER (ORDER BY datetime DESC) StartDate,. Function. Table 9. CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL functionality */ AS BEGIN RETURN (p_d2 - p_d1) * CASE UPPER (p_what) WHEN 'SS' THEN 24 * 60 * 60 WHEN 'MI' THEN 24 * 60 WHEN 'HH' THEN 24 ELSE NULL END; END;SELECT months_between ( date_1, date_2 )/12 years_between FROM employee. So, there’s. Apr 2, 2013 at 6:13. In SQL Server here's a little trick to do that: SELECT CAST(FLOOR(CAST(CURRENT_TIMESTAMP AS float)) AS DATETIME) You cast the DateTime into a float, which represents the Date as the integer portion and the Time as the fraction of a day that's passed. Syntax DATEDIFF (datepart ,startdate ,enddate) datepart Abbreviations year. Fractions are allowed; you can add 2. You need to use DATEADD - not DATEDIFF. date_open END. B. DATEDIFF( date_part , start_date , end_date) Code language: SQL (Structured Query Language) (sql) The DATEDIFF() function accepts three arguments: date_part, start_date, and end_date. Currently I am only returning 1. Only 10+ years later - here's a db<>fiddle which demonstrates the difference between subtracting a date from a date (e. You can't transform this value to date by to_date function. In Oracle, You can use the MONTHS_BETWEEN function with TRUNC and MOD function as follows: SQL> SELECT 2 TRUNC(TRUNC(MONTHS_BETWEEN(SYSDATE, DATE '2014-08. This is going to be short:. 18. g. Sorted by: 0. As you can see the EOMONTH function takes into account leap year. So you just have to multiply to get the result in minutes instead: SELECT (date2 - date1) * 24 * 60 AS minutesBetween FROM. . e. QUARTER: returns the quarter of the date. Just out of curiosity, have you paid the $95 for a manual yet? ;-) If not, get the thicker one when you do unless you are pretty familiar with the commands and just need a reference. SELECT date_part ('month',age ('2016-06-30', '2018-06-30')) The result of this query is 0. DATEDIFF(MONTH, 0, '2-14-2015') --returns month. Add a number of months (n) to a date and return the same day which is n of months away. HEH! One big difference you’ll find is that adding or subtracting two date values in Oracle leaves you with a number, not a date. Examples of Results in Months. I am having issues with DATE functions in SQL Plus. I don't think that you need to write your own timestampdiff function since oracle already has one: EXTRACT. Oracle's MONTHS_BETWEEN on the other hand tries to calculate an exact difference in months' fractions: select months_between(date '2021-02-01', date '2021-01-31') from dual; => 0. for the month differnce the standard sql is DATEDIFF, in this function you must pass 3 params, if you must calculate the difference from 2 columns, c1 and c2, you must do this query SELECT DATEDIFF(month,c1 , c2) FROM T WHERE. Delaying Execution. select datediff (q,'03-30-2005','04-01-2005') will return 1. Then type a formula like one of the following. Here’s the step by step: Use the AGE function to calculate the difference between the end date and start date. datediff() is not giving tHe result as I am working in Oracle. Difference of two dates in months user637544 Jun 1 2009 — edited Jun 1 2009 i need to find the difference of two dates as the number of months: find the last day. year, month, day), it takes into account only a certain element and higher elements in the time hierarchy – but not lower elements. date1. public static int MonthDiff (DateTime d1, DateTime d2) { int retVal = 0; // Calculate the number of years represented and multiply by 12 // Substract the month number from the total // Substract the difference of the second month and 12 from the total retVal. The Question asked for "6 months from the system date". . DateDiff compares the values of the column you specify to work out the difference, it doesn't compare both dates and give you an exact difference. 0. Improve this answer. I want to convert this number to years,Months,and Days. About; Products. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. The syntax for using the DATEDIFF function in Google BigQuery looks like the following:. This is the reason we cannot apply direct addition or subtraction on date. mm') month, 13 count(*) days 14 From calendar 15 group by to_char(datum, 'yyyy. date_from, evnt. 9. For many values of the local settings, this would simply fail. (The valid formats 1,7,10,11 will be described later. Share. 2. This function adds a specified number of days, months, and years to a given date. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. Share. Hi tom, I want day, month, minute and years difference everyting in seconds. TASKUNIQUEID, PROJ_TASK. Comparison with Excel DATEDIFF function. You also wouldn't prefix a function name with the @ sign. Syntax. If you want the "exact" (as far as floating point gets) average, use. Fractions are allowed; you can add 2. Again, the expected results would be a value of 1. Months "m" Quarters "q" Years "y" firstWeekDay (default value is 1) is a parameter that can be used if you are returning the length of time in weeks. Step 4: Change Data Type. Because the months are 06 in both dates. DaysInYear Returns the number of days in the specified year. The DATEPART () function returns an integer value that represents a specified part of the date of a given date. 1. The Oracle/PLSQL MONTHS_BETWEEN function returns the number of months between date1 and date2. Difference of two dates in months. Improve this answer. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. Modified 9 years, 7 months ago. select trunc ( (sysdate - to_date ('2012-02-28 15:20', 'YYYY-MM-DD hh24:mi')) / 24) from dual; You should have multiplied by. It has column UPDATED and CREATED. I tried going off of something like this: Select records from SQL Server if greater than 6 months but I get the error: Subquery returned more than 1 value. DATEDIFF does not guarantee that the full number of the specified time units passed between 2 datetime values: -- Get difference in hours between 8:55 and 11:00 SELECT DATEDIFF (hh, '08:55', '11:00'); -- Returns 3 although only 2 hours and 5 minutes passed between times -- Get difference in months between Sep 30, 2011 and Nov 02, 2011. from a date time value. Finding the seconds difference can be done as follows: SELECT (mod_date_time - create_date_time) * 24 * 60 * 60 as "seconds_diff" FROM t1. floor(months_between(sysdate, dateofbirth)/12) But, months_between function treats end of month day specially. DATEDIFF calculates the difference between two dates - it doesn't add day or months to an existing date. The first one involves getting the difference in days and then converting it to 'x year y month z days'. DAYS(date2 - date1). Instead, you can use simple arithmetic with Oracle dates, where subtracting one date from another gives the number of days, and where you can add an subtract days from a given date. date1. When the reporting date month is the same as the target month you can get a round up Here is a PostgreSQL function with the exact same behavior as the Oracle MONTHS_BETWEEN function. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. Syntax. Can Any one help me please. InDays) - (Pattern. Admission_Date) > 5. DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. This will return an interval that may look something like “1 year 2 months 3 days”. Example 3: Comparing dates for elapsed time (in months) since a given date: Using the DATEDIFF function, we can calculate the elapsed time in months from a specific date until the current date. DATEDIFF. SQL Server ignores that this is just one day. The first week of the year is 1. Calculate the last date of the month is quite simple calculation -. If date1 is earlier than date2, then the result is negative. For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. You can even find the number of hours, minutes, seconds, and so on in terms of details in between the two. (The valid formats 1,7,10,11 will be described later. Current Month. It means that the DATEPART function returns the number of times the boundary between two units is crossed. As another option you could use the months_between () function, and manipulate the value that gives you into the three parts. SS, which computes the difference in seconds. (Oct 2006 - June 2005 = 16) DP_WEEK returns the distance between the weeks capturing the input dates. ArrivalDate, Trips. I tried this in a query. One way to get our “DateDiff” function to exclude holidays and weekends is to have a calendar table pre-populated with some or all the information you need, and then use that table to exclude the dates. As another option you could use the months_between () function, and manipulate the value that gives you into the three. From the Oracle documentation: MONTHS_BETWEEN returns number of months between dates date1 and date2. Modified 2 years, 6 months ago. Currently, my code just returns zero on the right side of the decimal place. Here's the code provided by Tom Kyte at. How to generate days, weeks, or months between two dates in Oracle Database June 1, 2021 | 25 minute read Chris Saxon Developer Advocate There are. 6222691' DECLARE @date2 datetime2 = '2022-01-14 12:32:07. Stack Overflow. The @DATEDIFF calculation function for Essbase returns the difference between two input dates. How to unite two columns of date + time for datediff - Oracle sql. What I want to do is, given a date (say today) work out the correct Offset in the PatternDetail table for a given working pattern. hourEnd)) AS Expr1 FROM a INNER JOIN tp ON a. I have two Oracle columns (in a VIEW, not a table) - DateOfBirth and MembershipDate. 99. 3. The first quarter is 1, the last one is 4. · SELECT * FROM tbl WHERE dt. 9. proc sql noprint; create table daystoOverdue_list as select distinct business_object_rk , DateDiff (DAY, value_dt, Today ()) as value_dt from case_DataTable_d as tbl where tbl. Just divide the total by 7 to get the weeks and then calculate the remaining days. It should be 24 months. The number is the number of seconds elapsed since midnight, January 1, 1970. But your query is giving the last date of previous month. , for the Oracle database: sale_date >= TRUNC (sysdate) AND sale_date < TRUNC (sysdate + INTERVAL '1' DAY) Another common obfuscation is to compare dates as strings as shown in the following PostgreSQL example:Oracle/PLSQL - DateDiff. So if there are two dates separated by one day, the year difference can be 1 (see select datediff (year, '20141231', '20150101') ). DateDiff. As you can see it means that month. If the dates are really timestamps, then this is easy - subtract them and the result is a day to second interval. Viewed 516 times 0 Everyone, the table relationship diagram for the database is the below one. The schema is SYSIBM. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate. You'll get a more accurate result if you compute the difference between the two dates in days and divide by the mean length of a calendar year in days over a 400 year span (365. There are MANY way to compute the number of years between two dates in Oracle SQL. Then use these rules to set the column values: Start date: for the first row, return the input date; otherwise return the first of the month; End date: get the month start for the next row and subtract one day from it. first weeks into oracle. numeric-expression. , SYSDATE - pr. However, The. DP_MONTH returns the distance between the months capturing the input dates. SQL> ed Wrote file afiedt. EXTRACT (DAY from (first_date - second_date)) If for some reason, you do want to do that, then I don't think there is a datatype for the "datefield" keyword (YEAR, MONTH, DAY, etc). OutSystems can use both Oracle and MSSQL as its primary database. The two date fields are "timestamp" format (date and time). Syntax. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. 2. Javascript. References: ( found on on 05/15/2015 ) 1. I have a request to build a set of worksheets that accept an intial parameter - Start Date in the format MMM YYYY. The two date fields are "timestamp" format (date and time). So I am porting many SQL Procedures to Oracle. ROUND returns date rounded to the unit specified by the format model fmt. Syntax The syntax for the MONTHS_BETWEEN function in. SELECT DATEADD(MONTH, DATEDIFF(MONTH, 0, GETDATE()), 0) As First_Of_Current_Month , DateAdd(dd, -1, DateAdd(mm, DateDiff(mm, 0, GETDATE()) +1, 0)) As Last_Of_Current. idUsage Notes¶. created_date), 'HH24:MI:SS') This gets the difference between the dates as a. The difference in hours, minutes or seconds can be found by multiplying this number by 24, 24*60 or 24*60*60 respectively. Modified 3 years, 4 months ago. datediff; sysdate; Share. DECLARE @ADate DATETIME SET @ADate = GETDATE () SELECT DAY (EOMONTH (@ADate)) AS DaysInMonth. And lastly: I would strongly recommend using the ISO-8601 date format YYYYMMDD (here:. 4 Answers. 9. select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. User-1629274867 posted Hi, I have replaced MS Oracle Client with OPD. For weeks, i would just take your. Again, the expected results would be a value of 1. NEXT_DAY: Returns a datetime value that represents the first weekday, named by string-expression, that is later than the date inexpression. I thought the between operator use <= and >= so i should be getting anything on. A numeric value is returned. g. If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. Use DATEADD (): where HireDate < dateadd (year, -3, GETDATE ()) DATEDIFF () does not do what you think it does. Goal. The weekday (dw) datepart returns a number that. From the inputs you got there are 123 months between the date of 07/03/2011 to 24/3/2021. E. edited May 15, 2013 at 7:42. Two dates to calculate the number of days between. DateDiff. And you can use intervals, but using month intervals for. You can use this methodology to determine the first day of 3 months ago, and the last day of the previous month: select DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ())-3, 0) --First day of 3 months ago select DATEADD (MONTH, DATEDIFF (MONTH, -1, GETDATE ())-1, -1) --Last Day of previous month. I say ALL months as months can have 28 days (29 in a leap year), 30 days and 31 days which is why I wouldn't simply calculate the days between two dates. So, i need to unite them to one column to check if the time difference is lower the 5. Hot Network Questions Murder mystery, probably by Asimov, but SF plays a. For ex. CASE WHEN a. USE MASTER GO -. However, since you have known start- and end-dates then you can find the number of full years between the two bounds and then use an INTERVAL DAY TO. この数値は、1970年1月1日の深夜から経過した秒数です。. Should I change (edit) the title or delete and re-post the question properly? This is what I'm addressing. DateValue > DateAdd (day,-3,getdate ()) doing this in this way makes your. Base_DateDiff counts the number of days between the two dates. The dates do not have to be in the same format in the extract file, but the format of each must be supported. You can simply subtract two dates. · User1416329745 posted ANSI SQL 1992. This is not permitted when the subquery follows =, !=, <, <= , >, >= or when the. SELECT DATE '0016-08-03' - DATE '2016-07-08' FROM dual;-- -730461. Simply i need to convert this: SELECT FLOOR(DATEDIFF(NOW(),`startdate`)/365. Few examples of DATEDIFF: DATEDIFF - Example 1 Here, in this example, datepart is "day": SELECT DATEDIFF(day,'2016-06-05','2016-08-05') AS DiffDate Result: DiffDate 61 If the endDate has a day part less than startDate, it will get pushed to the previous month, thus datediff will give the correct number of months. For example. DOW: returns the day of the week, between Sunday (0) and Saturday (6) DOY: returns the day of the year. DATEDIFF(date1, date2) Parameter Values. Currently, my code just returns zero on the right side of the decimal place. If either expression is a character or graphic string, it must not be a CLOB. 0 months apart:Asked 3 years, 4 months ago. 25) AS `years`, COUNT(FLOOR(DATEDIFF(NOW(),`startdate`)/365. This can have results that you are not expecting. NEW_TIME returns the date and time in time zone timezone2 when date and time in time zone timezone1 are date. Syntax. date_open END. MonthDiff = DateDiff ("m", startdate, enddate) End If. DiffMonths ("05/01/95",. 2. Here are the 10 federal holidays a year, almost one per month: New Year’s Day on January 1; Martin Luther King’s Birthday on the. DatePart. The difference between 1st March 2011 and 29th February 2012 is 0. +1 This will work for every year difference. In the empty box, enter the date format that you want to use. Note that it is subtracting the second from the first, so you must have them in this order. We are now using NHibernate to connect to different database base on where our software is installed. – user330315. For example, with some sample dates: select months_between (date '2015-03-19', date '2012-01-06') as month_diff from dual; MONTH_DIFF ---------- 38. TIMESTAMPDIFF ( numeric-expression string-expression.